♦♣♥♠ Modified Yahtzee Challenge ♦♣♥♠

For this challenge we are going to make a modified version of the game Yahtzee:


To complete this challenge, we will use a list to manage our dice rolls. Some code to help you get started with this is shown here:

import random

#use a list to manage our 5 dice:
five_dice = []

#roll 5 dice, one at a time:
for roll in range(5):
    #each roll is between 1 and 6:
    dice_roll = random.randint(1,6)
    #join the roll to the list of dice:
    five_dice.append(dice_roll)

#show the list of five dice:
print(five_dice)

When you run this code, it will display the list of 5 dice as shown:

[3, 6, 3, 1, 4]

Your task is to process the list and determine if the following combinations exist. If more than one combination exists, the combination with the highest importance takes precedence. For example:

Combination	Example	Importance
No Pair	[2, 6, 4, 1, 3]	1
One Pair	[2, 6, 2, 1, 3]	2
Two Pair	[4, 1, 4, 5, 5]	3
Three of a Kind	[4, 1, 4, 4, 6]	4
Four of a Kind	[2, 2, 2, 3, 2]	5
Full House	[5, 5, 2, 5, 2]	6
Bottom Straight	[4, 3, 2, 5, 1]	7
Top Straight	[5, 6, 3, 4, 2]	8
Yahtzee	[4, 4, 4, 4, 4]	9

Some examples of your code running are shown here. Example 1:

[2, 1, 4, 6, 5]
No Pair

Example 2:

[6, 6, 2, 3, 6]
Three of a Kind

♦♣♥♠ Extension Yahtzee Challenge ♦♣♥♠

Using your code above, simulate n number of rolls, where n is an integer inputted by the user, and tally the results as follows:

Number of rolls: 5
[4, 5, 1, 2, 2]
[2, 6, 6, 6, 3]
[5, 1, 5, 1, 3]
[3, 2, 3, 6, 6]
[4, 2, 1, 5, 3]
No Pair: 0
One Pair: 1
Two Pair: 2
Three of a Kind: 1
Four of a Kind: 0
Full House: 0
Bottom Straight: 1
Top Straight: 0
Yahtzee: 0